Math, asked by lalitjogani5p9oeqi, 1 year ago

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Answered by Anonymous
1
use (a^2-b^2) identity

lalitjogani5p9oeqi: i used but it get wrong
Answered by siddhantjain248
2
a⁸-b⁸
= (a⁴)²-(b⁴)²
= (a⁴+b⁴) (a⁴-b⁴)
=(a⁴+b⁴) [(a²)²-(b²)²]
=(a⁴+b⁴) (a²+b²) (a²-b²)
=(a⁴+b⁴) (a²+b²) (a+b) (a-b)
Hope this answer helps you !!
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