expand x+1³ using any identity
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The expanded form of (x+1)3 is x3 + 3x2 +3x+ 1.
Explanation: We know that (x+y)3 = x3+y3+3xy(x+y).
Now, substitute y = 1 in the above formula, we get
(x+1)3 = x3+ 13 + 3(x)(1)(x+1)
(x+1)3 = x3+1+3x2+3x
(x+1)3 = x3+32+3x+1.
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