Question

experienced by the charge q.
Five identical charges Q are placed
equidistant on a semicircle as shown
in the figure. Another point charge q is
kept at the center of the circle of radius
R. Calculate the electrostatic force
-ko
y
Q
R​

Answer 1

Answer:

hope it helps

Explanation:

force exerted by each Q on q,

F = KQq/R?

see figure, force exerted by charge Q located at D is cancelled by force exerted by charge Q located at E.

all five charges are equidistant, so, angle made by two consecutive charge on centre of it = 90/5 = 18°

so, angle made by charges located at A and B = 2 x 18° = 36°

now, resultant of A and B = V{F? + F2 + = 2F+cos369 = FV{1 + 2 cos 36°), it is directed along x - axis.

now, net force experienced by q = force exerted by charge located at C + resultant of charge located at A and B.

= F+ FV[1+ 2 cos 36°}

putting F = KQq/R²,

now, Fnet = kQq/R?[1 + V(1 + 2 cos 236°)