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Answer:
20 days - Option(3).
Step-by-step explanation:
Given that A and B can complete a work in 12 days.
Therefore, 1/A + 1/B = (1/12) ---- (i)
According to the given condition,
=> A/2 + B/2 = 25
=> A + B = 50
=> A = 50 - B ----- (ii)
Substitute (ii) in (i), we get
⇒ 1/(50 - B) + 1/B = 1/12
⇒ 12B + 12(-B + 50) = B(-B + 50)
⇒ -B² + 50B - 600 = 0
⇒ B² - 50B + 600 = 0
⇒ B² - 20B - 30B + 600 = 0
⇒ B(B - 20) - 30(B - 20) = 0
⇒ (B - 20)(B - 30) = 0
⇒ B = 20,30
If B = 20:
A = 30
If B = 30:
A = 20.
Given that B is more efficient that A,he will take lesser time to do the job alone. Hence A will take 20 days and A will take 30 days.
Therefore,B will do the work in 20 days.
Hope it helps!
Step-by-step explanation:
Given that A and B can complete a work in 12 days.
Therefore, 1/A + 1/B = (1/12) ---- (i)
According to the given condition,
=> A/2 + B/2 = 25
=> A + B = 50
=> A = 50 - B ----- (ii)
Substitute (ii) in (i), we get
⇒ 1/(50 - B) + 1/B = 1/12
⇒ 12B + 12(-B + 50) = B(-B + 50)
⇒ -B² + 50B - 600 = 0
⇒ B² - 50B + 600 = 0
⇒ B² - 20B - 30B + 600 = 0
⇒ B(B - 20) - 30(B - 20) = 0
⇒ (B - 20)(B - 30) = 0
⇒ B = 20,30
If B = 20:
A = 30
If B = 30:
A = 20.
Given that B is more efficient that A,he will take lesser time to do the job alone. Hence A will take 20 days and A will take 30 days.