Explain how the resistance of the conductor varies if
A)length is doubled
B) area is doubled
C) area is halved
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. L=Length A=Area R=Resistivity ρ=constant According to the problem:- R= ρL/A Now if the length is doubled then area will be halved (bcoz the material of wire provided is fixed) A & B.......so if length is doubled and area is halved. new length=2L new area =A/2
so R =ρ4L/A (put the values)
so resistivity becomes 4 times the original
D.....Now if length is halved (area is doubled) new length=L/2 new area= 2A so
R=ρL / 4A
So resistivity becomes 1/4 th times
C......Length and area doubled new area=2A new length=2L
R =ρL/A
so Resistivity remains the same
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