Explain me all the three questions given in the attachment above
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In the figure,
- 5x + x + 80° + 123° + 85° = 360°
(Angles at a point)
- ⇒ 6x + 80° + 123° + 85° = 360°
- ⇒ 6x + 288° = 360°
- ⇒ 6x = 360° - 288 = 72°
- ⇒ x = 72°/6 = 12°
Now, ∠AOB = 5x = 5 × 12° = 60°
And ∠BOC = x = 12°
hope it's helps you
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In the figure,
5x + x + 80° + 123° + 85° = 360°
(Angles at a point)
⇒ 6x + 80° + 123° + 85° = 360°
⇒ 6x + 288° = 360°
⇒ 6x = 360° - 288 = 72°
⇒ x = 72°/6 = 12°
Now, ∠AOB = 5x = 5 × 12° = 60°
And ∠BOC = x = 12°tep-by-step explanation:
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