explain plzz The power of a lens is 6D Find the magnification produced by it for a real object placed at 15cm in front of it?a) 10b) -10c)1/10d) -1/10
Answers
Answered by
8
Given:
P=6D
u=-15cm
P=1/f
6=1/f
f=1/6(in m)
f=100/6(in cm)
lens formula:
1/f=1/v-1/u
multiply by u on both sides
u/v-1=u/f
1/m=-15x6/100+1
=1/10
m=10
so option a is correct
P=6D
u=-15cm
P=1/f
6=1/f
f=1/6(in m)
f=100/6(in cm)
lens formula:
1/f=1/v-1/u
multiply by u on both sides
u/v-1=u/f
1/m=-15x6/100+1
=1/10
m=10
so option a is correct
Answered by
2
Answer:
option a
Explanation:
Given that :
P=6D
u=-15cm
P=1/f
6=1/f
f=1/6(in m)
f=100/6(in cm)
By lens formula:
1/f=1/v-1/u
multiply by u on both sides :-
u/v-1=u/f
1/m=-15x6/100+1
=1/10
m=10
so option 'a' is correct.
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