Physics, asked by kuldeepkumar30, 11 months ago

explain rocket propulsion?

Answers

Answered by gouribmanoj
4

Rockets range in size from fireworks so small that ordinary people use them to immense Saturn Vs that once propelled massive payloads toward the Moon. The propulsion of all rockets, jet engines, deflating balloons, and even squids and octopuses is explained by the same physical principle: Newton’s third law of motion. Matter is forcefully ejected from a system, producing an equal and opposite reaction on what remains. Another common example is the recoil of a gun. The gun exerts a force on a bullet to accelerate it and consequently experiences an equal and opposite force, causing the gun’s recoil or kick.shows a rocket accelerating straight up. In part (a), the rocket has a mass m and a velocity v relative to Earth, and hence a momentum mv. In part (b), a time Δt has elapsed in which the rocket has ejected a mass Δm of hot gas at a velocity ve relative to the rocket. The remainder of the mass (m−m) now has a greater velocity (v+Δv). The momentum of the entire system (rocket plus expelled gas) has actually decreased because the force of gravity has acted for a time Δt, producing a negative impulse Δp=−mgΔt. (Remember that impulse is the net external force on a system multiplied by the time it acts, and it equals the change in momentum of the system. ) So the center of mass of the system is in free fall but, by rapidly expelling mass, part of the system can accelerate upward. It is a commonly held misconception that the rocket exhaust pushes on the ground. If we consider thrust; that is, the force exerted on the rocket by the exhaust gases, then a rocket’s thrust is greater in outer space than in the atmosphere or on the launch pad. In fact, gases are easier to expel into a vacuum.


image

Free-body diagram of rocket propulsion: (a) This rocket has a mass m and an upward velocity v. The net external force on the system is −mg, if air resistance is neglected. (b) A time Δt later the system has two main parts, the ejected gas and the remainder of the rocket. The reaction force on the rocket is what overcomes the gravitational force and accelerates it upward.


By calculating the change in momentum for the entire system over Δt, and equating this change to the impulse, the following expression can be shown to be a good approximation for the acceleration of the rocket.


a

=

v

e

m

Δ

m

Δ

t

g

where a is the acceleration of the rocket, ve is the escape velocity, m is the mass of the rocket, Δm is the mass of the ejected gas, and Δt is the time in which the gas is ejected.


gouribmanoj: Is this fine???
gouribmanoj: Thank you..
kuldeepkumar30: but this question is very tuf
gouribmanoj: I have learnt this in my Tution....
gouribmanoj: I go to Fiitjee...
kuldeepkumar30: thanks
gouribmanoj: My pleasure...
Answered by puhh12
2
DEAR HERE IS UR ANSWER
HOPE IT WILL HELP U

According to NASA rocket propulsion is When rockets leave the launch pad, they need a lot of power to lift them off the ground. Accomplishing this feat, however, isn't easy when you consider that rockets can weigh upwards of 4.4 million pounds.
Because of this massive weight, rockets have to rely on a powerful propulsion system. Rocket propulsion is the process that uses force to move a rocket off the ground and into the atmosphere.

rahulmehta23: hii
gouribmanoj: Hi
rahulmehta23: hiii gouri
gouribmanoj: Hi...
Similar questions
Math, 1 year ago