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Step-by-step explanation:
In Δ ABC, Using Heron's Formula, S = (a + b + c)/2 ⇒ S = (10 + 14 +16)/2 ⇒ S = 40/2 ⇒ S = 20 Area = ∴ Area of the triangles = ⇒ Area of Δ ABC = ⇒ Area = √4800 ⇒ Area = 10√48 ⇒ Area = 10√(2 × 2 × 2 × 2 × 3) ⇒ Area = 10 × 2 × 2√3 ⇒ Area of Δ ABC = 40√3 cm² ∴ Area of Δ ABC = 69.28 cm². We know, Area of the Δ ADC = Area of the ΔABC. [∵ Both the triangles are congruent) ∴ Area of the Parallelogram = 2 × Area of Δ ABC. ⇒ Area of the Parallelogram = 2 × 69.28 cm² ∴ Area of the Parallelogram = 138.56 cm². Hence, the Area of the Parallelogram is 138.56 cm². [ Note ⇒ The answer is different in points because I have taken the Exact value of √3. Although, it does not effect, such errors should be neglected.] á it helps
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Step-by-step explanation:
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