explain the chemistry ,BF3 reacts with F- to give BF4-, but AlF3 reacts with F- to give AlF63-.
Answers
Answer:
Boron can only form [BF
4
]
−
, whereas aluminum forms [AlF
6
]
3−
Reason
The first member of a group of elements in the s− and p−blocks shows anomalous behavior
we have to explain that BF₃ reacts with F¯ to give BF₄¯, but AlF₃ reacts with F¯ to give AlF₆³¯.
explanation : configuration of B = 1s², 2s², 2p¹
configuration of Al = 1s², 2s², 2p⁶ , 3s², 3p¹ , 3d⁰
here you see from configuration it is clear that boron doesn't have vacant d - orbital but Aluminium do have. due to this reason, Al atom has coordination number 6 while B atom has CN 4.
Hence due to non availability of d - orbitals in configuration of B atom, it forms BF₄¯ instead of BF₆³¯ but Al forms AlF₆³¯.
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