Question

Explain Why the decease in atomic radius from sodium to chloride is greater than that from of scandium to copper

Answer 1

Atomic radius is inversely proportional to the effective nuclear charge. As we move from left to right in a period the effective nuclear charge increases. This decreases the radius of an atom. At the same time, in transition elements the number of electrons in the 3d sub-shell will increase. This repels the already present 4s electrons. It increases the atomic radius. In Fe, Co, Ni & Cu both the effects nearly balance each other keeping the atomic radius same.

Answer 2

The decrease in atomic radius from sodium chloride is greater than that from scandium to Copper because:

● Atomic radius is contrarily corresponding I.e, inversely proportional to the compelling atomic charge.

● As we move from left to right in a period the viable atomic charge increments.

This reductions the sweep of a particle.

● Simultaneously, experiencing significant change components the quantity of electrons in the 3d sub-shell will increment.

● This repulses the effectively present 4s electrons. It expands the nuclear span.

● In Fe, Co, Ni and Cu both the impacts almost balance each other keeping the nuclear range same.