explain why the ionic radius of h- is greater than that of f- ion.
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In the case of hydrogen anion the only anion with electron to proton ratio (e/p) =2, as the nuclear charge is less comparable to number of electrons there is more repulsion because nuclear attraction is not good so the electron cloud will expand largely to overcome, resulting
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In the case of hydrogen anion the only anion with electron to proton ratio (e/p) =2, as the nuclear charge is less comparable to number of electrons there is more repulsion because nuclear attraction is not good so the electron cloud will expand largely to overcome, resulting
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