Question

explain with process 2^x-7=5^x-4

Answer 1

${2}^{x - 7} = {5}^{x - 4} \\ apply \: log \: on \: both \: sides \\ (x - 7)log2 = (x - 4)log5 \\ \frac{(x - 7)}{(x - 4)} = log(5 - 2) \\ x - 7 = xlog3 - 4log3 \\x(1 - log3) = 7 - 4log3 \\ x = \frac{(7 -4 log3)}{(1 - log3)} \\ x = 9.74$