Question

express 0.0bar12 in p/q form

Answer 1

Let x = 0.0121212.....

10x = 0.121212.... -------(1)

1000x = 12.121212.... -------(2)

On subtracting equation 1 from 2, we get

990x = 12

=> x = 12 /990

=> x = 4 / 330

=> x = 2 / 165

Required fraction = 2/ 165

Answer 2

0.01212=x ...1
multiply100on both sides
1.2212=100x.......2
subtract 1 from 2
1.21212=100x
-0.01212= -x
1.20000=99x
1.2=99x
x= 12/990