Question

Express 1.3222..+0.3535..as a fraction in simolest form

Answer 1

here's your answer, hope it helps !!!!!!!!!!!

Answer 2

Answer:

Step-by-step explanation:

                       Hey...

1.32(32 recurring) + 0.35( 35 recurring ) 

Le X= 1.323232323232323232.......(I) 

and 100X= 132.32323232323232323232......(II) Subtracting (I) from (II) gives 

99X=131 or X= 132/99 

Similarly let 

Y= 0.35353535353535.........(III) 100Y = 35.35353535353535353535......(IV) 

Subtracting (III) from (IV) gives 

99Y = 35 or Y= 35/99 

Hence 

1.32(32 recurring) + 0.35( 35 recurring ) 

=131/99+35/99= (131+35)/99= 166/99

Hope this helps..!!