Express 1-sqrt3i in the polar form.
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In polar form expressed as 2(cos300+isin300)
Explanation:
Let Z=1−(√3)i ; Modulus |Z|=(√12+(−√3)2)=2;tanθ=√−31ortanθ=√−3Argument θ=tan−1(√−3)=−600or3000.
In polar form expressed as |Z|⋅(cosθ+isinθ)or2(cos300+isin300)
Explanation:
Let Z=1−(√3)i ; Modulus |Z|=(√12+(−√3)2)=2;tanθ=√−31ortanθ=√−3Argument θ=tan−1(√−3)=−600or3000.
In polar form expressed as |Z|⋅(cosθ+isinθ)or2(cos300+isin300)
jamesnissy02:
Thanks bro
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