Question

Express 4.127127127... in the in the form for where pand a ause integers is not equal to o​

Answer 1

Given, the expression 1.4191919

Let 1.4191919=x  ⟹(i).

Multiplying (i) by 10,

⟹14.191919....=10x  ⟹(ii).

Multiplying (ii) by 1000,

⟹1419.191919....=1000x  ⟹(iii).

Then, (iii)−(ii)

⟹ 1000x−10x=1419.191919−14.191919

⟹ 990x=1405

⟹x=9901405=198281.

Hencs, 1.4191919 in qp is 198281.

Answer 2

Answer:

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