Question

Express 5-2√3 as irrational separately

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Lets take that 5-2√3 is a rational number.  

So we can write this number as  

5- 2√3 = a/b  

Here a and b are two co prime number and b is not equal to 0

Subtract 5 both sides we get  

-2√3 = a/b - 5

-2√3 = (a-5b)/b

Now divide by 2 we get  

-√3 = (a-5b)/2b

∴√3=-(a-5b)/2b

Here a and b are integer so -(a-3b)/2b is a rational number so √3 should be a rational number But √3 is a irrational number so it contradict the fact  

Hence result is 5-2√3 is a irrational number