Question

Express all trigonometric ratios in terms of sinA

Answer 1

HERE IS YOUR ANSWER.........

Answer 2

Good question:

Here's the answer

$sin^2A=1-cos^2A$........(1)

$sinA=1/cosecA$.......(2)

$sinA/cosA=tanA</p><p>=sinA=tanA*cosA</p><p>=sinA=tanA*\sqrt{1-sin^2A}$.......(3)

$tanA=1/cotA</p><p>sinA=\sqrt{1-sin^2A}/cotA$........(4)

$secA=1/cosA</p><p>cosA=1/secA</p><p>=cos^2A=1/sec^2A</p><p>=1-sin^2A=1/sec^2A</p><p>=sin^2A=1-1/sec^2A$..........(5)

Here are the relations

Hope this helps you

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