Question

Express latent heat of fusion and latent heat of vaporizations of water in j/g, kj/g and in kj/mol ?



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Answer 1

✔️✔️ QUESTION ✔️✔️

Express latent heat of fusion and latent heat of vaporizations of water in j/g, kj/g and in kj/mol ?

✔️✔️ ANSWER ✔️✔️

✔️The latent heat associated with melting a solid or freezing a liquidis called the heat of fusion

✔️The heat of fusion for water at 0 °C is approximately 334 joules (79.7 calories) per gram

✔️heat of vaporization at 100 °C is about 2,230 joules (533 calories) per gram

I HOPE THIS INFO HELPS YOU ☺️

#TEJ

Answer 2

Latent heat of fusion of water = 80 cal/g

= 80 × 4.184 j/g (1 cal = 4.184 j)

= 334.72 j/g

=0.335 kj/j

= 334.72 kj/kg

= 0.335 × 18 kg/mol (Molar mass of Water = 18)

= 6.03 kj/mol

Latent heat of vaporization of water = 540 cal/g

= 540 × 4.184 j/g

= 2259.3 j/g

= 2.2593 kg/g

= 2259.3 kj/kg

= 2.259 × 18 kj/mol

= 40.662 kg/mol