express the trignometric ratio of sin a in terms of cot a
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Answered by
1
cosec²A=1+cot²A
cosecA=√1+cot²A
We know sinA=1/cosecA
therefore sinA=1/√1+cot²A
cosecA=√1+cot²A
We know sinA=1/cosecA
therefore sinA=1/√1+cot²A
Answered by
3
we know that
cosec2a = 1+cot2a
cosec(a) = root(1+cot2a)
1/sina = root(1+cot2a)
then
Sina = 1/root(1+cot2a)
I hope it will help you..
cosec2a = 1+cot2a
cosec(a) = root(1+cot2a)
1/sina = root(1+cot2a)
then
Sina = 1/root(1+cot2a)
I hope it will help you..
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