Question

f a car moving with 36 km/hr increases its speed to 54 km/hr in 10 seconds, find (i) acceleration and (ii) distance covered by the car in this time. PLS ANSWER FAST

Answer 1

Initial speed = 36 km/h

Final speed = 72 km/h

Convert the speed to meter per second.

Kilometer to meter (km to m) :

Initial distance = 36 km = 36000 m

Final distance = 72 km = 72000 m

Convert an hour to seconds (hr to s) :

1 minute = 60 seconds

1 hr (60 minutes) = 3600 seconds

Speed = distance/time

Therefore,

Initial speed = 36000 m/3600 s = 10 m/s

Final speed = 72000 m/3600 s = 20 m/s

To get the acceleration produced

Acceleration = increase in speed in a particular direction / time

Change in speed in same direction = 20 m/s - 10 m/s = 10 m/s

Time of change = 5 seconds

Acceleration = (10 m/s )/ 5 s = 2 m/s^2

To get the distance covered during acceleration of the car

Distance covered = final distance - initial distance

That is, 72000 m - 36000 m = 36000 m