Question

f
$\frac{x + 1}{x + 2} = \frac{x - 3}{x + 4} = 0$
$\frac{2}{3} (x + 3) = \frac{1}{2} (x + 8)$

Answer 1

$\frac{2}{3}(x + 3) = \frac{1}{2} (x + 8) \\ \frac{2(x + 3)}{3} = \frac{1(x + 8)}{2} \\ \frac{2x + 6}{3} = \frac{x + 8}{2} \\ 2(2x + 6) = 3(x + 8) \\ 4x + 12 = 3x + 24 \\ 4x - 3x = 24 - 12 \\ x = 12$
if the answer is correct please mark as brainlist

Answer 2

(x+1) (x+4) = (x-3)(x+2)

= $x^{2}+5x+4 = x^{2} -x-6$

 6x = -10

x = -10/6=> -5/3
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$\frac{2}{3}(x+3)= \frac{1}{2}(x+8)$

4 (x+3) = 3( x+8) 

4x + 12 = 3x + 24 

x = 12