Question

F the magnitude of the position vector of the point (-3, k, 12) is 13 units, find the possible values of k.

Answer 1

We can measure the position vector origin that is given ( 0, 0, 0) to (-3, k, 12) equals to 13

We know distance formula [(x2-x1)^2+(y2-y1)^2+(z2-z1)^2]^1/2

=-3^2+k^2+12^2=13^2

=k^2=169-153

K=4