Question

f the sum of the zeroes of the quadratic polynomial 2x² – (2k + 1)x + (3k – 1) is half of the product of its zeroes, then what is the value of k?

Answer 1

sum of the equation=(2k+1)/2

product of the equation=(3k-1)/2

ATP,

(2k+1)/2=((3k-1)/2)/2

(2k+1)/2=(3k-1)/4

(2k+1)=(3k-1)/2

(2k+1)*2=(3k-1)

4k+2=3k-1

4k-3k=-1-2

k=-3