Math, asked by ketu36, 1 year ago

f(x) =4x^3+3x^2-2x+5 and integration f(x) dx is​

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Answered by ihrishi
3

Answer:

f(x) = 4 {x}^{3}  + 3 {x}^{2}  - 2x + 5 \\ \therefore  \int \: f(x) =  \int(4 {x}^{3}  + 3 {x}^{2} - 2x + 5) \: dx \\  =  4\int {x}^{3}dx  + 3\int {x}^{2} dx- 2 \int \: x \: dx  + 5 \int \: 1 \: dx \\  = 4 \times  \frac{ {x}^{4} }{4}  + 3  \times  \frac{ {x}^{3} }{3}  - 2 \times  \frac{ {x}^{2} }{2}  + 5x \:  + c \\ =   {x}^{4}  +  {x}^{3}  -  {x}^{2}  + 5x + c \:  \\  \therefore \:  \int \: f(x) =   {x}^{4}  +  {x}^{3}  -  {x}^{2}  + 5x + c  \:

Answered by mmainak968
0

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