Question

f(x)= }(x+1)(x+2) -
then limf(x)=​

Answer 1

Answer:

2

Step-by-step explanation:

$f(x)=x^2+3x+2$

The part missed out here is  

$lim \lim_{x \to\00} x^2+3x+2$

Since this question has a constant not dependent on x, we may simply put in x = 0, and we get the limit, that is 2.

Edit: Ignore the first lim in the equation, I typed it by mistake...