Q. Find the common difference of an arithmetic progression whose first term is 5 and the sum of its first 4 terms is half the sum of the next 4 terms ???
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Answer- 8/5
Step-by-step explanation:
a = 4
a+a2+a3+a4 = (a5+a6+a7+a8)/2
4+4+d+4+2d+4+3d = (4+4d+4+5d+4+6d+4+7d)/2
16+6d = (16+22d)/2
16+6d = 2(8+11d)/2
16+6d= 8+11d
16-8=11d-6d
8= 5d
d=8/5
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