facrorise question no. 10 plz fast
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3a^2 b - 12a^2 - 9b + 36
= (3a^2b - 9b ) - (12a^2 -36)
= 3b(a^2 - 3) - 12(a^2 - 3)
= (3b - 12)(a^2 - 3) (ans)
= (3a^2b - 9b ) - (12a^2 -36)
= 3b(a^2 - 3) - 12(a^2 - 3)
= (3b - 12)(a^2 - 3) (ans)
ash40:
thx
can u plz factorise question no 13 also plz fase
can u plz factorise question no 13 also plz fast
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10. 3a²b-12a²-9b+36=3a²(b-4)-9(b-4)
=(b-4)(3a²-9)
=(b-4)[(√(3)a)²-3²]
=(b-4)(√3a-3)(√3a+3)
13.a(b-c)-d(c-b)=a(b-c)+d(b-c)
=(b-c)(a+d)
=(b-4)(3a²-9)
=(b-4)[(√(3)a)²-3²]
=(b-4)(√3a-3)(√3a+3)
13.a(b-c)-d(c-b)=a(b-c)+d(b-c)
=(b-c)(a+d)
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