Question

factarise the following​

Answer 1

Answer:

2(x + y + 1) .

Step-by-step explanation:

Given expression is;

             ⇒   $\frac{8(x^{3} y^{2}z^{2} + x^{2} y^{3}z^{2} +x^{2} y^{2}z^{2} )}{4x^{2} y^{2} z^{2} }$

             ⇒   $\frac{8x^{2}y^{2} z^{2} (x +y +1 )}{4x^{2} y^{2} z^{2} }$   [ by taking $x^{2} y^{2} z^{2}$ common from numerator ]

             ⇒   2(x + y + 1)  [ because common things gets canceled out ]