Solve the following equation for value of 'x' :
(Note: Absurd answers are constantly showing the stupidity of his/her answer. So please, don't do this!)
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here is your answer
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√3x² - 2√2x - 2√3. = 0
√3x² - 3√2x + √2x - 2√3 = 0
√3x(x - √6) + √2(x - √6) = 0
(x - √6)(√3x + √2) = 0
so, x-√6 = 0 or √3x + √2 = 0
x = √6 or x = -√2/√3
HOPE IT HELPS YOU ☺☺
√3x² - 3√2x + √2x - 2√3 = 0
√3x(x - √6) + √2(x - √6) = 0
(x - √6)(√3x + √2) = 0
so, x-√6 = 0 or √3x + √2 = 0
x = √6 or x = -√2/√3
HOPE IT HELPS YOU ☺☺
kunaljangid2k3:
Shouldn't there be root 2 in 4th line?
how
yaa sorry
now it's ok..
now it's ok..
Well, you got me confused at that!
ok
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