Question

Factor of equation 2x^4-5x^2+3=0

Answer 1

Answer:

√2or√3/2

Step-by-step explanation:

Now the given equation is 2x^4−5x^2+3=0

Let x^2 = t

Hence the new equation will become

2t^2–5t+3=0

now the simple formula for quadratic equation would be

t =[ -b±√(b^2 - 4ac) ]/ 2a

where a, b are coefficients of t^2 and t respectively, and c is the constant.

Hence according to our equation, a=2, b=-5, c=3

∴t =[ -(-5)±√((-5)^2 -4x2x3)]/2x2

∴t=[5±√(25–24)]/4

∴t=[5±1]/4

∴t=2, or t=3/2

Now resubstituting t=x^2

∴x^2=2 or x^2=(3/2)

∴x=√2 or x=√(3/2)

HOPE YOU ARE SATISFIED WITH MY ANSWER