Question

factories 27x³+y³+2³-9xy² ​

Answer 1

$\huge\bold\red{꧁ᴀɴsᴡᴇʀ࿐}$

27x3+y3+z3−9xyz

=(3x)3+y3+z3−9xyz

=(3x)3+y3+z3−3×3x×y×z

using identity

a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)

Putting a=3x,b=y,c=z

=(3x+y+z)(9x2+y2+z2−3xy−yz−3zx)

Answer 2

$\huge\boxed{\underline{\mathcal{\red{❥A}\green{N}\pink{S}\orange{W}\blue{E}\purple{R}}}}$

27x3+y3+z3−9xyz

=(3x)3+y3+z3−9xyz

=(3x)3+y3+z3−3×3x×y×z

using identity

a3+b3+c3−3abc=(a+b+c)(a2+b2+c2−ab−bc−ca)

Putting a=3x,b=y,c=z

=(3x+y+z)(9x2+y2+z2−3xy−yz−3zx)