Question

factorise. 1-(b-c)^2

Answer 1

 

Given equation :- 1 - ( b - c )^2

           Method 2

1 - ( b - c )^2

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We know,

( a )^2 - ( b )^2 = ( a - b )( a + b )

Applying the formula given above in the question.

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1^2 - ( b - c )^2

{ 1 - ( b - c ) } { 1 + ( b - c ) }

{ 1 - b + c }{ 1 + b - c }

Therefore, 1 - ( b -c )^2 = ( 1 - b + c )( 1 + b - c )

$\:$

Answer 2

Answer:

(1+b-c)(1-b+c)

Step-by-step explanation:

=1^2-(b-c)^2

=[1-(b-c)][1+(b-c)]

Therefore, (1+b-c)(1-b+c)