Question

factorise 121a^2- 88ab+ 16b^2

Answer 1

Answer:

121 a² - 88ab + 16 b². ⇒ (11a)² - 2 * 11a * 4b + (4b)². ⇒ ( 11a - 4b )². IDENTITY USED: a² - 2ab + b² = (a - b)².

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Answer 2

Here is your solution...

121a^2-88ab+16b^2

(11a)^2 - 2x11ax4b + (4b)^2

(11a-4b)^2 (from (a-b)^2 identity)

Since we have to factorise,

Therefore the correct solution will be,

(11a-4b)(11a-4b)

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