Question

factorise 216m^3-27n^3

Answer 1

to factorise the above equation we have
216m^3-27n^3
we can write this as
(6m)^3-(3n)^3
by using the identity we have
a^3-b^3=(a-b)(a^2+b^2+ab)
now,we have
(6m-3n)(36m^2+9n^2+18mn)
Answer

Answer 2

Ello!!

Here's your answer

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Factorise of the following:-

216 m^3 - 27 n^3

= ( 6m )^3 - ( 3n )^3

= ( 6m - 3n ) { ( 6m )^2 + 6m × 3n + ( 3n )^2 }

= 3 ( 2m - n ) ( 36m^2 + 18mn + 9n^2 )

= 3 ( 2m - n ) × 9 ( 4m^2 + 2mn + n^2 )

= 27 ( 2m - n ) ( 4m^2 + 2mn + n^2 )

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Hope it helps you dear!

★ Devil king