Question

Factorise :
24d + 32d³​

Answer 1

Following are the steps for getting the answer:

Given:

24d + 32d³​

To find:

factor of 24d + 32d³​

Solution:

we have to find the factor of 24d + 32d³​

we use the grouping method

24d + 32d³​

we will write this

32d³​+24d

now take 8d the common

we get,

8d(4d²+3)

Hence, the factor of 24d + 32d³​ is 8d(4d²+3)

Answer 2

To factorize :  $24 d + 32d^{3}$

Solution :

• To factorize $24 d + 32d^{3}$ we find factors of both terms

1. $24 \times d = 3\times 2\times 2\times 2\times d$
2. $32 d^{3} = 2\times 2\times2 \times2\times 2\times d\times d\times d$

• Now , substituting factors

        $24 d + 32d^{3}$  $= ( 3\times 2\times 2\times2\times d ) + ( 2\times 2\times2\times 2\times 2\times d\times d\times d )$

• Taking $(2\times 2\times 2\times d)$ common we get ,

         $= (2\times 2\times 2\times d)[ ( 3) + ( 2\times 2\times d\times d)]$  

• Also it can be written as   $8d ( 3 + 4d^{2})$

       Hence factors of $24d + 32d^{3}$ are  $8d ( 3 + 4d^{2})$

 

                             

      Hence , factors of  are  .