Question

factorise 28p²q²r-42pq²r²
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Answer 1

Answer:

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:

24x2+25x−47=(−8x−3)(ax−2)−53

You should then multiply (−8x−3) and (ax−2) using FOIL.

24x2+25x−47=−8ax2−3ax+16x+6−53

Then, reduce on the right side of the equation

24x2+25x−47=−8ax2−3ax+16x−47

Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.

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Answer 2

Answer:

Look first we have to take out the L.C.M of 28 and 42

and then we have to calculate which has came in outside like we have 7 and 2 outside so we have to multiply that so answer will come 14 so we will put that outside with the common alphabets shown in the picture nd then u just have to write in the bracket the answer which came like 2 and 3 then we will arrange it so the answer will come

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