Question

Factorise:
(2x-1)²-(x-1)(x-3)-1

Answer 1

Answer:

$= (2x - 1) {}^{2} - (x - 1)(x - 3) - 1 \\ = 4x {}^{2} - 4x + 1 - x {}^{2} + 3x + x - 3 - 1 \\ = 3x {}^{2} - x - 4 \\ = 3x {}^{2} - 4x + 3x - 4 = 0 \\ = x(3x - 4) + 1(3x - 4) = 0 \\ = (3x - 4)(x + 1) = 0 \\ \\ x = \frac{4}{3} \\ \\ x = - 1$

Step-by-step explanation:

Hope it helps you.........❤️

please mark it as brainliest........✌️

Answer 2

Answer:

1;-1

Step-by-step explanation:

(2x-1)^2=(x-1)(x-3)+1

(2x)^2 +1^2-2*2x*1=x^2-3x-x+3+1

4x^2+1-4x=x^2-4x+4

4x^2-x^2-4x+4x+1-4=0

3x^2-3=0

3x^2=3

x^2=3/3

x^2= 1

x=√1

x= 1 ; -1