Question

factorise 2x^2-5xy-2y^2​

Answer 1

SOLUTION:-

${2x}^{2} - 5xy - {2y}^{2} \\ \\ = > {2x}^{2} - 5xy + {2y}^{2} = 0 \\ \\ = > {2x}^{2} - 4xy - xy + {2x}^{2} = 0 \\ \\ = > 2x(x -2y) - y(x - 2y) = 0 \\ \\ = > (x - 2y)(2x - y) = 0 \\ \\ = > x - 2y = 0 \: \: \: or \: \: \: 2x - y = 0 \\ \\ = > x = 2y \: \: or \: \: 2x = y \\ \\ = > x = 2y \: \: \: or \: \: x = \frac{y}{2}$

Hope it helps ☺️

Answer 2

Answer:

Step-by-step explanation: