Question

Factorise
2x^2+ y^2+8z^2+2√2xy+ 4√2yz -8xz ​

Answer 1

2x²+y²+8z²+2√2xy+4√2yz-8xz

=(-√2x)²+(y)²+(2√2z)²+(2)(-√2x)(y)+(2)(y)(2√2z)+(2)(-√2x)(2√2z)

=(-√2x+y+2√2z)

using identity,

[(a+b+c)²= a²+b²+c²+2ab+2bc+2ca]