Math, asked by ItsShizuka01, 6 months ago

Factorise 2x^3 - 5x^2 - 19x + 4​

Answers

Answered by Aɾꜱɦ
1

Step-by-step explanation:

Answer:

\huge\underline\textsf{Question:- }

\boxed{\sf2x ^{3}  - 5x {}^{2}  - 19x + 42}

\huge\underline\textsf{Explantion:- }

\leadsto\sf\red{2x {}^{3}  - 4x {}^{2}  - x {}^{2}  + 2x - 21x + 42}

\leadsto\sf\orange{2x {}^{2} (x - 2) - x(x - 2) - 21(x - 2)}

\leadsto\sf\purple{(x - 2)(2x {}^{2}  - x - 2)}

\leadsto\sf\blue{(x - 2)(2x {}^{2}  + 6x - 7x - 21)}

\leadsto\sf\pink{(x - 2)(2x {}^{2}  + 6x - 7x - 21)}

\leadsto\sf\orange{(x - 2)[(2x(x + 3) - 7(x + 3)]}

\leadsto\sf\red{(x - 2)(2x - 7)(x + 3)}

\large\underline\textsf{\green{Ans.(x - 2)(2x - 7)(x + 3)} }

Answered by Anonymous
17

Answer:

Question

Factorise 2x^3 - 5x^2 - 19x + 4

\huge\underline\mathcal\red{♡ĂnSwer♡}

=> 2x³ - 5x² - 19x + 42

=> 2x³ - 4x² - x² + 2x -21x + 42

=> 2x²(x - 2) -x(x - 2) - 21(x - 2)

=> (x - 2) ( 2x² - x - 21)

=> (x - 2) ( 2x² - 7x + 6x - 21)

=> (x - 2) ( 2x² + 6x - 7x - 21)

=> (x - 2) ( 2x( x + 3) -7( x + 3) )

=> (x - 2) (2x - 7) (x + 3)

Thanks..

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