factorise 2x^5+432x^2y^3
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Answered by
23
Let's simplify step-by-step.2x2(5)+432x22y23=10x2+432x22y23Answer:=432x22y23+10x2
Answered by
90
2x^5 + 432x^2y^3
=We will take 2x^2 common from both terms
we get, x^3+216y^3
We know that a^3+b^3 = (a+b)(a^2+b^2-ab)
Now,(x)^3+(6y)^3
= 2x^2(x+6y)(x^2+36y^2-6yx)
=We will take 2x^2 common from both terms
we get, x^3+216y^3
We know that a^3+b^3 = (a+b)(a^2+b^2-ab)
Now,(x)^3+(6y)^3
= 2x^2(x+6y)(x^2+36y^2-6yx)
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