Question

factorise (2x2+7x-15)​

Answer 1

HEYA USER ❤️

2x²+7x-15

By splitting middle term,

2x²+10x-3x-15

2x(x+5)-3(x+5)

(x+5)(2x-3) Required factors

Answer 2

HEYA USER❤️❤️❤️❤️

STEP BY STEP EXPLANATION ------

$2 {x}^{2} + 7x - 15$

This expression can be expressed as factors in the form of MIDDLE TERM FIRST STAGE.

They are as follows.........

$2 {x}^{2} + 7x - 15$

Multiplying the extremities i.e. –15*+2 = –30x^2

....

Now the numeric term –30 has to be expressed in such a way that the factors imply the result 7 in either addition or subtraction.

To determine whether the factors will be added or subtracted, we should see the product's sign. If the product's sign is minus then there would be minus breaking and if the product's sign is plus then there would be plus breaking. Here, product's sign is minus so there would be minus breaking.

$2 {x}^{2} + 7x - 15 \\ = 2 {x}^{2} + x(10 - 3) - 15$

I have done the breaking with 10 and 3.

REMEMBER

I have not removed the numeric feom it's place. It is remained as it is.

............

$= 2 {x}^{2} + 10x - 3x - 15 \\ = 2x(x + 5) - 3(x + 5) \\ =( x + 5)(2x - 3)$

1st line - opening the bracket

2nd line - taking common

3rd line - taking common

ANSWER:-

(x+5)(2x-3)

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