Math, asked by arifhussain01971, 6 months ago

factorise 2y^ 7 - 128y​

Answers

Answered by yogeshvishwakarma123
0

Answer:

2y^7-128y= 2y(y^6-64)

2y (y^6-2^6)

2y [(y^3)^2-(2^3)^2]

2y[(y^3+2^3) (y^3-2^3)]

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