Question

factorise: 2y³+y²-2y+1​

Answer 1

Given expression :-

2y³ + y² - 2y + 1 = 0

Taking out 'y'....

y(2y² + y -2) + 1 = 0

y( 2y² + y - 1) = 0

y( 2y² - y + 2y - 1) = 0

y[y(2y-1) +1 ( 2y -1)] = 0

y[(2y-1)(y+1)] = 0

(2y-1)(y+1) = 0

If product of two terms is zero then either first term is equal to zero or second term is equal to zero.

2y-1 = 0 or y + 1 = 0

y = 1/2 or y = -1