factorise:2ycube+ysquare-2y-1
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hope it will help you ☺️
silu12
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Hello Mate!
= 2y³ + y² - 2y - 1
= y² ( 2y + 1 ) - 1 ( 2y + 1 )
= ( 2y + 1 )( y² - 1 )
= ( 2y + 1 )[ y² - 1² ]
= ( 2y + 1 )( y + 1 )( y - 1 )
How to factorise?
Try to take common factors out. Note the factors you make should me in multiplication.
Verification :
= ( 2y + 1 )( y² - 1 )
= 2y( y² - 1 ) + 1( y² - 1 )
= 2y³ - 2y + y² - 1
= 2y³ + y² - 2y - 1
Hence Proved.
Have great future ahead!
= 2y³ + y² - 2y - 1
= y² ( 2y + 1 ) - 1 ( 2y + 1 )
= ( 2y + 1 )( y² - 1 )
= ( 2y + 1 )[ y² - 1² ]
= ( 2y + 1 )( y + 1 )( y - 1 )
How to factorise?
Try to take common factors out. Note the factors you make should me in multiplication.
Verification :
= ( 2y + 1 )( y² - 1 )
= 2y( y² - 1 ) + 1( y² - 1 )
= 2y³ - 2y + y² - 1
= 2y³ + y² - 2y - 1
Hence Proved.
Have great future ahead!
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