Question

Factorise: 3√3a³+27b³-c³+9√3abc

Answer 1

hey mate this is your answer 3+3,+27,_ 3+9+3,abc

Answer 2

Answer :-

Given polynomial

$3 \sqrt{3} {a}^{3} + 27 {b}^{3} - {c}^{3} + 9 \sqrt{3} abc$

Now we know this Identity that

${a}^{3} + {b}^{3} + {c}^{3} - 3abc \: \\ = (a + b + c)\times \\( {a}^{2} + {b}^{2} + {c}^{2} - ab \: - bc \: - ca)$

Now

as coefficient of

a = √3

b = 3

c = -1

Then factorization

$= (\sqrt{3} a + 3b - c)\times \\(3 {a}^{2} + 9 {b}^{2} + c - 3 \sqrt{3}ab + 3bc \: + \sqrt{3} ca)$

Hope it helps