Math, asked by jagdish1581, 1 year ago

Hello guys answer fast ASAP​

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Answers

Answered by sameer5288
1

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AND HOPE IT WILL HELP !!!

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Answered by SunHelpingHand
0

Given PQRS is the diameter of circle of radius 10.5cm

So...

PS=10.5×2=21cm

Given PQ=QR=RS

So PQ=7cm, QR=7cm, RS=7cm

➡️So perimeter of the shaded portion of area= [π×(21/2)]+[π×(7/2)]+[π×(14/2)]

=33+77+22= 132cm

➡️ Area of the non-shaded portion=

[(π/2)×(21/2)²]+[(π/2)×(14/2)²]- [(π/2)×(7/2)²]

=231cm²

Hope it helped u


jagdish1581: hmm
jagdish1581: ya I know the perimeter
jagdish1581: hmmm
jagdish1581: ok
jagdish1581: tq bye
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