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Given PQRS is the diameter of circle of radius 10.5cm
So...
PS=10.5×2=21cm
Given PQ=QR=RS
So PQ=7cm, QR=7cm, RS=7cm
➡️So perimeter of the shaded portion of area= [π×(21/2)]+[π×(7/2)]+[π×(14/2)]
=33+77+22= 132cm
➡️ Area of the non-shaded portion=
[(π/2)×(21/2)²]+[(π/2)×(14/2)²]- [(π/2)×(7/2)²]
=231cm²
Hope it helped u
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