Factorise: 3a3 + 3b3 + 2a + 2b.
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Factorise 1. ... By taking (3a – 2b) in the given question, ... 3 + (1 − 2) − 2 2 ... − 7. ... √ + √ + − √ .
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3(a3+b3)+2(a+b)
a3+b3=(a+b)(a2+b2-ab)
3(a+b)(a2+b2-ab)+2(a+b)
(a+b)[3(a2+b2-ab)+2]
(a+b)(3a2+3b2-3ab+2)
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